Wrong Input Through scanf, What Happens?

scanf does not assign the value entered in case of wrong input.

Go through the following lines of code:

#include<stdio.h>

#include<conio.h>

void main(){

int x=100;

scanf("%d", &x);

printf("Value of x is = %d", x);

getch();

}

Now the scanf is supposed to scan an integer value. Take 2 cases where you input:

(i) 2

(ii) d (or any character)

In (i) printf prints Value of x is = 2.

In (ii) printf prints Value of x is = 100.

Note that when you give wrong input to scanf, it does not assign any value to x and so the previous value of x is retained.

PS1: Compiler used TurboC.
PS2: Corrections/Suggestions/Comments are welcome!